Tìm x, biết: a) (8x2 – 4x) : (−4x) – (x + 2) = 8; b) (2x4 – 3x3 + x2) : (−x2) + 4(x – 1)2 = 0.

a) (8x² – 4x) : (−4x) – (x + 2) = 8

−2x + 1 – x – 2 = 8

−3x = 9

x = −3.

Vậy x = −03.

b) (2x⁴ – 3x³ + x²) : (−x²) + 4(x – 1)² = 0

−2x² + 3x – 1 + 4x² – 8x + 4 = 0

2x² – 5x + 3 = 0

2x² – 2x – (3x – 3) = 0

2x(x – 1) – 3(x – 1) = 0

(x – 1)(2x – 3) = 0

x – 1 = 0 hoặc 2x – 3 = 0

x = 1 hoặc x=32

Vậy x∈1;  32.