Tìm x, biết: a) 5x + 7 = 2.
Giải thích
a)\(5x + 7 = 2\)
\(5x = 2 - 7\)
\(5x = - 5\)
\(x = - 1\)
b)\(4 + \sqrt x = 20\)
\[\sqrt x = 16\]
\(x = {16^2}\)
\(x = 256\)
c) \({\left( {x + 2} \right)^2} = 16\)
\({\left( {x + 2} \right)^2} = {4^2}\)
TH1: \(x + 2 = 4\)
\(x = 2\)
TH2: \(x + 2 = - 4\)
\(x = - 6\)