Tìm x, biết: a) 5,4:x = - 1,2;b) - 5/6 - x = 2/3;

a) \(5,4:x =  - 1,2\)

    \(x = 5,4:\left( { - 1,2} \right)\)

    \(x =  - 4,5\).

Vậy \(x =  - 4,5\).

b) \( - \frac{5}{6} - x = \frac{2}{3}\)

    \(x =  - \frac{5}{6} - \frac{2}{3}\)

    \(x =  - \frac{3}{2}\)

Vậy \(x =  - \frac{3}{2}\).

c) \(\frac{1}{9} - {\left( {2x + \frac{1}{2}} \right)^2} = 0\)

    \({\left( {2x + \frac{1}{2}} \right)^2} = \frac{1}{9}\)

Trường hợp 1:

\(2x + \frac{1}{2} = \frac{1}{3}\)

\(2x = \frac{1}{3} - \frac{1}{2}\)

\(2x =  - \frac{1}{6}\)

\(x =  - \frac{1}{{12}}\)

Vậy \(x \in \left\{ { - \frac{1}{{12}}; - \frac{5}{{12}}} \right\}\).

Trường hợp 2:

\(2x + \frac{1}{2} =  - \frac{1}{3}\)

\(2x =  - \frac{1}{3} - \frac{1}{2}\)

\(2x =  - \frac{5}{6}\)

\(x =  - \frac{5}{{12}}\)