Tìm x biết: 4x^2 - 9 - (3 - 2x)(x - 4) = 0

4x2 – 9 – (3 – 2x)(x – 4) = 0

⇔ 4x2 – 9 – (3x – 12 – 2x2 + 8x) = 0

⇔ 4x2 – 9 – 3x + 12 + 2x2 – 8x = 0

⇔ 6x2 – 11x + 3 = 0

⇔ (3x – 1)(2x – 3) = 0

⇔ 

Vậy