Tìm x: a)11/8-3/8.x = 1/8;

10/13

Tìm \[x\]:

a) \[\frac{{11}}{8} - \frac{3}{8} \cdot x = \frac{1}{8}\]; b) \({\left( {{\rm{x}} - \frac{1}{2}} \right)^{\rm{2}}}{\rm{ = }}\frac{{\rm{1}}}{4}\).

Nhập câu trả lời ở đây

0/3000 ký tự

Giải thích

a) \[\frac{{11}}{8} - \frac{3}{8} \cdot x = \frac{1}{8}\]

\[\frac{3}{8} \cdot x = \frac{{11}}{8} - \frac{1}{8}\]

\[\frac{3}{8} \cdot x = \frac{{10}}{8}\]

\[x = \frac{{10}}{8}:\frac{3}{8}\]

\[x = \frac{{10}}{3}\].

Vậy \[x = \frac{{10}}{3}\].

b) \({\left( {x - \frac{1}{2}} \right)^2} = \frac{1}{4}\)

• TH1: \(x - \frac{1}{2} = \frac{1}{2}\)

\(x = \frac{1}{2} + \frac{1}{2}\)

\(x = 1\).

• TH2: \(x - \frac{1}{2} = \frac{{ - 1}}{2}\)\(x = \frac{{ - 1}}{2} + \frac{1}{2}\)

\(x = 0\).

Vậy \(x = 1\,;\,\,\,x = 0\).