Tìm (x-1)^3= 1/8

\({\left( {x - 1} \right)^3} = \frac{1}{8}\)

\({\left( {x - 1} \right)^3} = {\left( {\frac{1}{2}} \right)^3}\)

\(x - 1 = \frac{1}{2}\)

\(x = 1 + \frac{1}{2}\)

\(x = \frac{3}{2}\)