tìm tích phân 1/3^x dx
Giải thích
\(\int {\frac{1}{{{3^x}}}} dx = \int {{{\left( {\frac{1}{3}} \right)}^x}} dx = \frac{{{{\left( {\frac{1}{3}} \right)}^x}}}{{\ln \frac{1}{3}}} + C = - \frac{1}{{{3^x}\ln 3}} + C\).
\(\int {\frac{1}{{{3^x}}}} dx = \int {{{\left( {\frac{1}{3}} \right)}^x}} dx = \frac{{{{\left( {\frac{1}{3}} \right)}^x}}}{{\ln \frac{1}{3}}} + C = - \frac{1}{{{3^x}\ln 3}} + C\).