Tìm số tự nhiên x, biết: a) 192 - x = 16.  b) 69 + (x + 16) = 185

a) \(192 - x = 16\)

\(x = 192 - 16\)

\(x = 176\)

Vậy \(x = 176\).

b) \(69 + \left( {x + 16} \right) = 185\)

\(x + 16 = 185 - 69\)

\(x + 16 = 116\)

\(x = 116 - 16\)

\(x = 100\)

Vậy \(x = 100\).

c) \(\left[ {{{\left( {x - 1} \right)}^3} - {4^2}} \right].3 = 327\)

\({\left( {x - 1} \right)^3} - 16 = 327:3\)

\({\left( {x - 1} \right)^3} - 16 = 109\)

\[{\left( {x - 1} \right)^3} = 109 + 16\]

\({\left( {x - 1} \right)^3} = 125 = {5^3}\)

\(x - 1 = 5\)

\(x = 6\)

Vậy \(x = 6\).