Tìm số nguyên x, biết 3 / 2x+1 + 10 / 4z+2 - 6 / 6x+3 = 12/26
Giải thích
32x+1+104x+2−66x+3=1226⇒32x+1+1022x+1−632x+1=1226⇒32x+1+52x+1−22x+1=1226⇒3+5−22x+1=1226⇒62x+1=613⇒2x+1=13⇒x=6
32x+1+104x+2−66x+3=1226⇒32x+1+1022x+1−632x+1=1226⇒32x+1+52x+1−22x+1=1226⇒3+5−22x+1=1226⇒62x+1=613⇒2x+1=13⇒x=6