Tìm nguyên hàm: I=∫sin^4 x / cos^2 x dx
Giải thích
Chọn B.
I=∫sin4xcos2xdx
=∫1cos2x+cos2x-2dx=tanx -2x+∫dx2+14∫cos2xd(2x)=tanx-32x+14sin2x+C
= tanx - 1,5x + 0,25 sin2x + C
Chọn B.
I=∫sin4xcos2xdx
=∫1cos2x+cos2x-2dx=tanx -2x+∫dx2+14∫cos2xd(2x)=tanx-32x+14sin2x+C
= tanx - 1,5x + 0,25 sin2x + C