Tìm nguyên hàm của hàm số f(x)=căn bậc 3 (3x+13)
Giải thích
Chọn C
∫f(x)dx=∫3x+13dx=∫3x+113d(3x+1)3 =13∫(3x+1)13d(3x+1)=13(3x+1)4343+C⇒∫f(x)dx=143x+13x+13+C
Chọn C
∫f(x)dx=∫3x+13dx=∫3x+113d(3x+1)3 =13∫(3x+1)13d(3x+1)=13(3x+1)4343+C⇒∫f(x)dx=143x+13x+13+C