176 Bài trắc nghiệm Hàm số từ đề thi Đại học cực hay có lời giải chi tiết (P3)

Tìm m để hàm số y=mx^3 - (m^2 + 1)x^2 + 2x - 3 đạt

10/30

Tìm m để hàm số y=mx3-(m2+1)x2+2x-3 đạt cực tiểu tại x=1.

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Rsyz10qDwpEpZ2bkGE15KscPwBEGAtu4E05eNV4wFkv5WCwN6uHksfwDOb-1PtNhrm8pnfnapQHITEG_BR1_jiqMX7W12gjr-rQJ7StF8MCQ_iTPfPNjTkZ3TdhVeMW9dHiOKjaF3w89jIYQZA.

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Giải thích

Chọn A

Ta có: h2a074z59vPm0ogK_hKau3Y0TbCGB9RmtLT0aOrvKnqE6NR8PZNHgmlZCPqTBfrC6MqkMlEX-k84hsksuxLwdSR9_Mi4d5NVzW4HiRVtnoXoRxgiF9d_MI2MN9tG-pk0VNVnDfAHb_5MiYjyEw, 8sU-h7Hf3Xf7z0uMIEN9WKoMLcFkV6Ncv512Lne3V0U4APW0A5zmPtdm75g4oecOlS4MmXoui9icNns5MqnrHIcBpMvq9DM4d-WHUuhXdKgHHJHWv5VQcj2FSXk5RblnBmjXEjzc5PW9HbGGfQ.

Để hàm số đã cho đạt cực tiểu tại x=1

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jUIdRGieL7qGN6jBAXWhc4DHse3CNXWvGNe3jhf0ncR4Im44RFONpM2RSokIHH7KCHKVVPJme_dBEInQoRL1KybDyy76KyqT-cEEfZLS559HwCeRGhAj8a-l4L7oo7J3X3CPR-M29_IosMiriw

r2v2wH2lhyJLWEomhpLBPMnTpVyULlHHp9HZrd46sf48EFDoHKnITdMM-ZylcloTnXcI4jP-n_O055RssMsa5vu_Rc5CRWGGubNC_i_sTu1EhoN50YBN2q_fO0Jxhfr5R3aQfWCDunLv1gxf2Q

Q8T0CH3tMXujlZdq3bGH0_b7ELGMhEVxiGyxy9LdF0952XmTDxigMIrh3cayLhHFqEaroyPzrZwJTTQFIzqcxLas9j1fmrAyAOdOqSuxMXN7i1Y9r1kbHzm2CHsHGR-fzEgyhcR02VeG2mPJ0w.