Tìm Lim {{{x^3} - căn {3x - 2} } / {x^2} - 1

\(\begin{array}{l}\mathop {\lim }\limits_{x \to 1} \left( {\frac{{{x^3} - 1}}{{{x^2} - 1}} - \frac{{\sqrt {3x - 2} - 1}}{{{x^2} - 1}}} \right)\\\mathop {\lim }\limits_{x \to 1} \left( {\frac{{{x^2} + x + 1}}{{x + 1}} - \frac{{3(x - 1)}}{{(x - 1)(x + 1)(\sqrt {3x - 2} + 1)}}} \right)\\\mathop {\lim }\limits_{x \to 1} \left( {\frac{{{x^2} + x + 1}}{{x + 1}} - \frac{3}{{(x + 1)(\sqrt {3x - 2} + 1)}}} \right) = \frac{3}{2} - \frac{3}{4} = \frac{3}{4}\end{array}\)