Tìm góc lượng giác x sao cho: sin(x - 60 độ) = - căn bậc hai 3 / 2

Do \(\sin \left( { - 60^\circ } \right) = - \frac{{\sqrt 3 }}{2}\) nên sin(x – 60°) = \( - \frac{{\sqrt 3 }}{2}\)⇔ sin(x – 60°) = sin(– 60°)

\( \Leftrightarrow \left[ \begin{array}{l}x - 60^\circ = - 60^\circ + k360^\circ \\x - 60^\circ = 180^\circ - \left( { - 60^\circ } \right) + k360^\circ \end{array} \right.\left( {k \in \mathbb{Z}} \right)\)

\( \Leftrightarrow \left[ \begin{array}{l}x = k360^\circ \\x = 300^\circ + k360^\circ \end{array} \right.\left( {k \in \mathbb{Z}} \right)\).