Tìm giới hạn: lim 2n- căn 4n^2 +n/ n+ căn n^2 -2n .
Giải thích
Ta có:
limn−n2−2n=limn−n2−2nn+n2−2nn+n2−2n=limn2−n2+2nn+n2−2n=lim2nn+n2−2n
=lim21+1−2n=1
Suy ra lim2n−4n2+nn+n2−2n=−14.
Ta có:
limn−n2−2n=limn−n2−2nn+n2−2nn+n2−2n=limn2−n2+2nn+n2−2n=lim2nn+n2−2n
=lim21+1−2n=1
Suy ra lim2n−4n2+nn+n2−2n=−14.