Tìm giới hạn C=lim (x->3)( că (2x+3)-x)/(x^2-4x+3)
Giải thích
Chọn C
C=limx→32x+3−xx2−4x+3=limx→32x +3−x2(x- 3). (x- 1). (2x+3+x) =limx→3−(x−3)(x+1)(x−3)(x−1)2x+3+x=limx→3−(x+1)(x−1)2x+3+x=−(3+1)(3−1).(2.3+3+3)=−13
Chọn C
C=limx→32x+3−xx2−4x+3=limx→32x +3−x2(x- 3). (x- 1). (2x+3+x) =limx→3−(x−3)(x+1)(x−3)(x−1)2x+3+x=limx→3−(x+1)(x−1)2x+3+x=−(3+1)(3−1).(2.3+3+3)=−13