Tìm giá trị của x , biết: (a) 2 x + 3/24 = 3 x − 1/32 ; (b) x ( 2 x − 5 ) + ( 4 x^3 − 6 x^2 − 6 x ) : ( − 2 x ) = 19 .

a) \[\frac{{2x + 3}}{{24}} = \frac{{3x - 1}}{{32}}\]

\[\frac{{2x + 3}}{3} = \frac{{3x - 1}}{4}\]

\(3.\left( {3x - 1} \right) = 4.\left( {2x + 3} \right)\)

\(9x - 3 = 8x + 12\)

\(x = 15\)

Vậy \(x = 15\).

b) \(x\left( {2x - 5} \right) + \left( {4{x^3} - 6{x^2} - 6x} \right):\left( { - 2x} \right) = 19\)

\(2{x^2} - 5x + \left( { - 2{x^2} + 3x + 3} \right) = 19\)

\(2{x^2} - 5x - 2{x^2} + 3x + 3 = 19\)

\( - 2x = 16\)

\(x = - 8\)

Vậy \(x = - 8\).