Tìm giá trị của x , biết: (a) 2 x + 1/6 = 3 − x^9 ; (b) ( 24 x^4 + 16 x^2 ) : ( − 8 x^2 ) + 3 x ( x − 6 ) = − 26 .

a) \(\frac{{2x + 1}}{6} = \frac{{3 - x}}{9}\)

\(9\left( {2x + 1} \right) = 6\left( {3 - x} \right)\)

\(18x + 9 = 18 - 6x\)

\(24x = 9\)

\(x = \frac{9}{{24}} = \frac{3}{8}\)

Vậy \(x = \frac{3}{8}\).

b) \(\left( {24{x^4} + 16{x^2}} \right):\left( { - 8{x^2}} \right) + 3x\left( {x - 6} \right) = - 26\)

\(24{x^4}:\left( { - 8{x^2}} \right) + 16{x^2}:\left( { - 8{x^2}} \right) + 3x.x + 3x.\left( { - 6} \right) = - 26\)

\( - 3{x^2} - 2 + 3{x^2} - 18x = - 26\)

\( - 18x = - 24\)

\[x = \frac{{ - 24}}{{ - 18}} = \frac{4}{3}\]

Vậy \[x = \frac{4}{3}\].