Tìm giá trị của x , biết: 2x + 3/4 = 7/6

a) \(2x + \frac{3}{4} = \frac{7}{6}\)

\[2x = \frac{7}{6} - \frac{3}{4}\]

\[2x = \frac{5}{{12}}\]

\(x = \frac{5}{{24}}\)

Vậy \(x = \frac{5}{{24}}\).

b) \(\left| x \right| - \frac{1}{2} = \frac{3}{4}\)

\(\left| x \right| = \frac{3}{4} + \frac{1}{2}\)

\(\left| x \right| = \frac{5}{4}\)

\(x = \pm \frac{5}{4}\)

Vậy \(x = \pm \frac{5}{4}\).

c) \({\left( {x - \frac{1}{2}} \right)^2} - \frac{1}{3} = \frac{{23}}{{12}}\)

\({\left( {x - \frac{1}{2}} \right)^2} = \frac{9}{4}\)

\(x - \frac{1}{2} = \frac{3}{2}\) hoặc \(x - \frac{1}{2} = - \frac{3}{2}\)

\(x = 2\) hoặc \(x = - 1\)

Vậy \(x \in \left\{ {2; - 1} \right\}\).

d) \(\left( {\frac{2}{3}x - \frac{4}{9}} \right) \cdot \left( {\frac{1}{2} + x} \right) = 0\)

\(\frac{2}{3}x - \frac{4}{9} = 0\) hoặc \(\frac{1}{2} + x = 0\)

\(\frac{2}{3}x = \frac{4}{9}\) hoặc \(x = - \frac{1}{2}\)

\(x = \frac{2}{3}\) hoặc \(x = - \frac{1}{2}\)

Vậy \(x \in \left\{ {\frac{2}{3}; - \frac{1}{2}} \right\}\).