Giải SGK Toán 12 CTST Bài 1. Nguyên hàm có đáp án

Tìm: a) nguyên hàm của (2x^5 +3) dx ; b) nguyên hàm (5cos x -3 sinx)dx

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Tìm:

a) ∫2x5+3dx;                                  b) ∫5cosx−3sinxdx;

c) ∫x2−2xdx;                                 d) ∫ex−2−2sin2xdx.

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Giải thích

a) \(\int {\left( {2{x^5} + 3} \right)dx} \)\( = 2\int {{x^5}dx} + 3\int {dx} \)\( = \frac{{{x^6}}}{3} + 3x + C\).

b) \(\int {\left( {5\cos x - 3\sin x} \right)dx} \)\( = 5\int {\cos xdx} - 3\int {\sin xdx} \)\( = 5\sin x + 3\cos x + C\).

c) \(\int {\left( {\frac{{\sqrt x }}{2} - \frac{2}{x}} \right)} dx\)\( = \frac{1}{2}\int {{x^{\frac{1}{2}}}} dx - 2\int {\frac{1}{x}} dx\)\( = \frac{1}{3}{x^{\frac{3}{2}}} - 2\ln \left| x \right| + C\)\( = \frac{1}{3}x\sqrt x - 2\ln \left| x \right| + C\).

d) \(\int {\left( {{e^{x - 2}} - \frac{2}{{{{\sin }^2}x}}} \right)dx} \)\( = \frac{1}{{{e^2}}}\int {{e^x}dx} - 2\int {\frac{1}{{{{\sin }^2}x}}dx} \)\( = \frac{{{e^x}}}{{{e^2}}} + 2\cot x + C\)\( = {e^{x - 2}} + 2\cot x + C\).