Tích phân I=1/2x-1 bằng
Giải thích
Cách 1.
\(I = \int\limits_1^2 {\frac{1}{{2x - 1}}} \;{\rm{d}}x = \left. {\frac{1}{2}\ln |2x - 1|} \right|_1^2\)
\( = \frac{1}{2}(\ln 3 - \ln 1) = \frac{1}{2}\ln 3 = \ln \sqrt 3 .\)
Cách 1.
\(I = \int\limits_1^2 {\frac{1}{{2x - 1}}} \;{\rm{d}}x = \left. {\frac{1}{2}\ln |2x - 1|} \right|_1^2\)
\( = \frac{1}{2}(\ln 3 - \ln 1) = \frac{1}{2}\ln 3 = \ln \sqrt 3 .\)