Bộ 10 đề thi giữa kì 2 Toán 6 Kết nối tri thức có đáp án - Đề 10

Thực hiện phép tính (tính nhanh nếu có thể): a) 5/17- 25/31 + 12/17 + - 6/31;

5/9

II. PHẦN TỰ LUẬN

Thực hiện phép tính (tính nhanh nếu có thể):

a) \(\frac{5}{{17}} - \frac{{25}}{{31}} + \frac{{12}}{{17}} + \frac{{ - 6}}{{31}}\);                                          b) \(\frac{{17}}{8}:\left( {\frac{{23}}{8} + \frac{{ - 9}}{2}} \right)\);

c) \(\frac{3}{4}.\frac{{11}}{{27}} + \frac{{16}}{{27}}.\frac{3}{4} + \frac{1}{2}\);                                                           d) \(\frac{{27}}{{23}} - \frac{{ - 5}}{{21}} - \frac{4}{{23}} + \frac{{16}}{{21}} + \frac{1}{2}\).

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Giải thích

a) \(\frac{5}{{17}} - \frac{{25}}{{31}} + \frac{{12}}{{17}} + \frac{{ - 6}}{{31}}\)= \(\left( {\frac{5}{{17}} + \frac{{12}}{{17}}} \right) + \left( {\frac{{ - 6}}{{31}} - \frac{{25}}{{31}}} \right)\)

= \(\left( {\frac{{5 + 12}}{{17}}} \right) + \left( {\frac{{ - 6 - 25}}{{31}}} \right)\)= \(\frac{{17}}{{17}} + \frac{{ - 31}}{{31}} = 1 + ( - 1) = 0\).

b) \(\frac{{17}}{8}:\left( {\frac{{23}}{8} + \frac{{ - 9}}{2}} \right)\)=  \(\frac{{17}}{8}:\left( {\frac{{23}}{8} + \frac{{ - 36}}{8}} \right)\)= \(\frac{{17}}{8} & :\frac{{23 + \left( { - 36} \right)}}{8}\)

= \(\frac{{17}}{8} & :\frac{{ - 13}}{8}\)= \(\frac{{17}}{8} & .\frac{8}{{ - 13}} = \frac{{17}}{{ - 13}} = \frac{{ - 17}}{{13}}\).

c) \(\frac{3}{4}.\frac{{11}}{{27}} + \frac{{16}}{{27}}.\frac{3}{4} + \frac{1}{2}\)\[ = \frac{3}{4}.\left( {\frac{{11}}{{27}} + \frac{{16}}{{27}}} \right) + \frac{1}{2}\]

\[ = \frac{3}{4}.\frac{{27}}{{27}} + \frac{1}{2}\]\[ = \frac{3}{4} + \frac{1}{2} = \frac{3}{4} + \frac{2}{4} = \frac{5}{4}\].

d) \(\frac{{27}}{{23}} - \frac{{ - 5}}{{21}} - \frac{4}{{23}} + \frac{{16}}{{21}} + \frac{1}{2}\)\( = \left( {\frac{{27}}{{23}} - \frac{4}{{23}}} \right) + \left( {\frac{{16}}{{21}} - \frac{{ - 5}}{{21}}} \right) + \frac{1}{2}\)

\( = \left( {\frac{{27 - 4}}{{23}}} \right) + \left( {\frac{{16 + 5}}{{21}}} \right) + \frac{1}{2}\)\( = \frac{{23}}{{23}} + \frac{{21}}{{21}} + \frac{1}{2} = 1 + 1 + \frac{1}{2}\)

\( = 2 + \frac{1}{2} = \frac{4}{2} + \frac{1}{2} = \frac{5}{2}\).