Thực hiện phép tính (tính hợp lí nếu có thể): a) 3/4 + 1/4 . − 12/20 ; b) 5 6/7 . ( − 5/6 + 1/7 ) + 41/7 . ( − 1/6 + 6/7 ) ;
a) \(\frac{3}{4} + \frac{1}{4}.\frac{{ - 12}}{{20}}\) \( = \frac{3}{4} + \frac{{ - 3}}{{20}}\) \( = \frac{{15}}{{20}} + \frac{{ - 3}}{{20}}\) \( = \frac{{12}}{{20}}\) \( = \frac{3}{5}\). | b) \(5\frac{6}{7}.\left( { - \frac{5}{6} + \frac{1}{7}} \right) + \frac{{41}}{7}.\left( { - \frac{1}{6} + \frac{6}{7}} \right)\) \[ = \frac{{41}}{7}.\left( { - \frac{5}{6} + \frac{1}{7}} \right) + \frac{{41}}{7}.\left( { - \frac{1}{6} + \frac{6}{7}} \right)\] \[ = \frac{{41}}{7}.\left( { - \frac{5}{6} + \frac{1}{7} - \frac{1}{6} + \frac{6}{7}} \right)\] \[ = \frac{{41}}{7}.\left[ {\left( { - \frac{5}{6} - \frac{1}{6}} \right) + \left( {\frac{1}{7} + \frac{6}{7}} \right)} \right]\] \[ = \frac{{41}}{7}.\left( { - 1 + 1} \right)\] \[ = \frac{{41}}{7}.0\] = 0. | c) \({2^2}.\sqrt {16} - {\left( {\sqrt 7 } \right)^2}\) \( = 4.4 - 7\) = 16 – 7 = 9.
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