Thực hiện phép tính (tính hợp lí nếu có thể): a) (( 2^4 )^3 .5 ^9)/( 25^4 .2^11) ; b) √ 29 + 7 . 4/ 3 + ∣ ∣ − 8/ 3 ∣ ∣ ;
a) \[\frac{{{{\left( {{2^4}} \right)}^3}{{.5}^9}}}{{{{25}^4}{{.2}^{11}}}} = \frac{{{2^{12}}{{.5}^9}}}{{{{\left( {{5^2}} \right)}^4}{{.2}^{11}}}} = \frac{{{{2.5}^9}}}{{{5^8}}} = 2.5 = 10\];
b) \(\sqrt {29 + 7} .\frac{4}{3} + \left| { - \frac{8}{3}} \right| = \sqrt {36} .\frac{4}{3} + \frac{8}{3} = 6.\frac{4}{3} + \frac{8}{3} = \frac{{24}}{3} + \frac{8}{3} = \frac{{32}}{3}\);
c) \[\left( {\frac{1}{6} - \frac{5}{8}} \right).2\frac{1}{3} + \left( {\frac{5}{6} + \frac{{21}}{8}} \right):\frac{3}{7} = \left( {\frac{1}{6} - \frac{5}{8}} \right).\frac{7}{3} + \left( {\frac{5}{6} + \frac{{21}}{8}} \right).\frac{7}{3}\]
\[ = \left( {\frac{1}{6} + \frac{5}{6} - \frac{5}{8} + \frac{{21}}{8}} \right).\frac{7}{3} = \left( {\frac{6}{6} + \frac{{16}}{8}} \right).\frac{7}{3} = \left( {1 + 2} \right).\frac{7}{3} = 7\].