Thực hiện phép tính: a) (x + 5)(3x+2y). b) (3x - 2)^2 - (x + 3)(x - 3)
Hướng dẫn giải
a) \[\left( {x + \;5} \right)\left( {3x + \;2y} \right)\] \[ = 3{x^2} + 2xy + 15x + 10y.\] | b) \[{\left( {3x - \;2} \right)^2}\; - \;\left( {x + \;3} \right)\left( {x - \;3} \right)\] \[ = 9{x^2} - 12x + 4 - \left( {{x^2} - 9} \right)\] \[ = 9{x^2} - 12x + 4 - {x^2} + 9\] \[ = 8{x^2} - 12x + 13\] | c) \[\frac{5}{{x + 1}}\; - \frac{2}{{x - 1}}\; + \frac{{4x}}{{{x^2} - 1}}\] \[ = \frac{{\;5\;}}{{x + \;1}} - \frac{2}{{x - 1}} + \frac{{4x}}{{\left( {x\; + \;1} \right)\left( {x\; - 1} \right)}}\] \[ = \frac{{\;5\left( {x\; - 1} \right) - 2\left( {x\; + \;1} \right) + 4x\;}}{{\left( {x\; + \;1} \right)\left( {x\; - 1} \right)}}\] \[ = \frac{{\;5x - 5 - 2x - 2 + 4x\;}}{{\left( {x\; + \;1} \right)\left( {x\; - 1} \right)}}\] \[ = \frac{{\;7\left( {x\; - 1} \right)\;}}{{\left( {x\; + \;1} \right)\left( {x\; - 1} \right)}} = \frac{{\;7\;}}{{x\; + \;1}}.\] |