Thực hiện phép tính: a) 4x +3y/ x^2 -y^2 -3x +4y/ x^2 -y^2 ;
Giải thích
a) 4x+3yx2−y2−3x+4yx2−y2=(4x+3y)−(3x+4y)x2−y2
=4x+3y−3x−4y(x+y)(x−y)=(4x−3x)+(3y−4y)(x+y)(x−y)
=x−y(x+y)(x−y)=1x+y;
a) 4x+3yx2−y2−3x+4yx2−y2=(4x+3y)−(3x+4y)x2−y2
=4x+3y−3x−4y(x+y)(x−y)=(4x−3x)+(3y−4y)(x+y)(x−y)
=x−y(x+y)(x−y)=1x+y;