Bộ 5 đề thi giữa kì 1 Toán 7 Cánh diều (2022-2023) có đáp án - Đề 4

Thực hiện phép tính: 7/6 + 1/6.3/2

Giải thích

a) \(\frac{7}{6} + \frac{1}{6}\,\,.\,\,\frac{3}{2}\)

 \( = \frac{7}{6} + \frac{1}{4}\)

 \( = \frac{{28}}{{24}} + \frac{6}{{24}}\)

 \( = \frac{{17}}{{12}}\)

b)\[\frac{{11}}{{15}}\,\,.\,\,\frac{{ - 19}}{{13}} + \frac{{ - 7}}{{13}}\,\,.\,\,\frac{{11}}{{15}}\]

 \[ = \frac{{11}}{{15}}\,\,.\,\,\left( {\frac{{ - 19}}{{13}} + \frac{{ - 7}}{{13}}} \right)\]

 \[ = \frac{{11}}{{15}}\,\,.\,\,\left( {\frac{{ - 26}}{{13}}} \right)\]

 \[ = \frac{{ - 22}}{{15}}\].

c)\(\frac{{{2^3} + {2^4} + {2^5} + {2^6}}}{{{{15}^2}}}\)

 \( = \frac{{{2^3}\left( {1 + 2 + {2^2} + {2^3}} \right)}}{{{{15}^2}}}\)

 \( = \frac{{{2^3}\,.\,\,15}}{{{{15}^2}}}\)

 \[ = \frac{{{2^3}}}{{15}} = \frac{8}{{15}}\]