Thực hiện phép tính 7/6 - 1/6:2/3
Giải thích
a) \(\frac{1}{3} + \frac{2}{5}.\frac{5}{3} = \frac{1}{3} + \frac{2}{3} = 1\);
b) \({\left( {\frac{{ - 1}}{7}} \right)^7}:{\left( {\frac{1}{7}} \right)^7} = {\left( {\frac{{ - 1}}{7}:\frac{1}{7}} \right)^7} = {\left( {\frac{{ - 1}}{7}.\frac{7}{1}} \right)^7} = {\left( { - 1} \right)^7} = - 1\);
c) \({2^4} + 8\,\,.\,\,{\left[ {{{\left( { - 2} \right)}^2}:\frac{1}{2}} \right]^0}\frac{1}{{{2^2}}}\,\,.\,\,4 + {\left( { - 2} \right)^2}\)
\( = 16 + 8.1 - \frac{1}{4}\,.\,4 + 4\)\( = 16 + 8 - 1 + 4 = 27\).