Thực hiện phép tính: 1/x^2+3x+2+2/x^2+12x+35+3/x^2+7x+10
Giải thích
1x2+3x+2+2x2+12x+35+3x2+7x+10=1x+1x+2+2x+5x+7+3x+2x+5
=1x+1−1x+2+1x+5−1x+7+1x+2−1x+5=1x+1−1x+7=6x+1x+7
1x2+3x+2+2x2+12x+35+3x2+7x+10=1x+1x+2+2x+5x+7+3x+2x+5
=1x+1−1x+2+1x+5−1x+7+1x+2−1x+5=1x+1−1x+7=6x+1x+7