Thực hiện phép tính: 1/(x^2+3x+2)-2x/(x^3+4x^2+4x)+1/(x^2+5x+6)
Giải thích
=(x+2)(x+3)−2(x+1)(x+3)+(x+1)(x+2)(x+1)(x+2)2(x+3)=x2+5x+6−2x2−8x−6+x2+3x+2(x+1)(x+2)2(x+3)=2(x+1)(x+2)2(x+3)
=(x+2)(x+3)−2(x+1)(x+3)+(x+1)(x+2)(x+1)(x+2)2(x+3)=x2+5x+6−2x2−8x−6+x2+3x+2(x+1)(x+2)2(x+3)=2(x+1)(x+2)2(x+3)