so sánh p với 1/3
Giải thích
ĐKXĐ: a > 0; a ≠ 1.
a) \(P = \left( {\frac{1}{{\sqrt a - 1}} - \frac{1}{{\sqrt a }}} \right):\left( {\frac{{\sqrt a + 1}}{{\sqrt a - 2}} - \frac{{\sqrt a + 2}}{{\sqrt a - 1}}} \right)\)
\(P = \frac{1}{{\left( {\sqrt a - 1} \right)\sqrt a }}:\frac{{a - 1 - a + 4}}{{\left( {\sqrt a - 1} \right)\left( {\sqrt a - 2} \right)}}\)
\(P = \frac{1}{{\left( {\sqrt a - 1} \right)\sqrt a }}:\frac{3}{{\left( {\sqrt a - 1} \right)\left( {\sqrt a - 2} \right)}}\)
\(P = \frac{1}{{\left( {\sqrt a - 1} \right)\sqrt a }}.\frac{{\left( {\sqrt a - 1} \right)\left( {\sqrt a - 2} \right)}}{3}\)
\(P = \frac{{\sqrt a - 2}}{{3\sqrt a }}\)
b) Xét
Vậy \(P < \frac{1}{3}\)