So sánh A= 1/3+ 1/3^2+ 1/3^3+....+ 1/3^99 với 1/2
Giải thích
Ta có: 3A=3(13+132+133+...+1399)=(1+13+132+133+...+1398)
Suy ra 3A−A=1−1399
2A=1−1399⇒A=12−12.399<12
Vậy A=13+132+133+...+1399<12
Ta có: 3A=3(13+132+133+...+1399)=(1+13+132+133+...+1398)
Suy ra 3A−A=1−1399
2A=1−1399⇒A=12−12.399<12
Vậy A=13+132+133+...+1399<12