Rút gọn biểu thức: C=(a^2−căna)/(a+căna+1)−(a^2+căna)/(a−căna+1)+a+1
Giải thích
C=a2−aa+a+1−a2+aa−a+1+a+1 (DK:a≥0)C=a(a)3−1a+a+1−a(a)3+1a−a+1+a+1=a(a−1)−a(a+1)+a+1=a−a−a−a+a+1=a-12
C=a2−aa+a+1−a2+aa−a+1+a+1 (DK:a≥0)C=a(a)3−1a+a+1−a(a)3+1a−a+1+a+1=a(a−1)−a(a+1)+a+1=a−a−a−a+a+1=a-12