Rút gọn biểu thức: 3(2^2 + 1)(2^4 + 1)(2^8 + 1)(2^16 + 1)
Giải thích
322+122+128+1216+1=22-122+124+128+1216+1(vì 22-1=4-1=3)=24-124+128+1216+1=28-128+1216+1=216-1216+1=232-1
322+122+128+1216+1=22-122+124+128+1216+1(vì 22-1=4-1=3)=24-124+128+1216+1=28-128+1216+1=216-1216+1=232-1