Phân tích thành nhân tử: x^5 x^4 x^3 x^2 x 1
Giải thích
Lời giải:
x5 + x4 + x3 + x2 + x + 1
= (x + 1) (x4 + x3 + x2 – x3 + 1)
= (x + 1) [x2(x2 + x + 1) – (x3 – 1)]
= (x + 1) [x2(x2 + x + 1) – (x – 1)(x2 + x + 1)]
=(x + 1)(x2 + x + 1)(x2 – x + 1)
Lời giải:
x5 + x4 + x3 + x2 + x + 1
= (x + 1) (x4 + x3 + x2 – x3 + 1)
= (x + 1) [x2(x2 + x + 1) – (x3 – 1)]
= (x + 1) [x2(x2 + x + 1) – (x – 1)(x2 + x + 1)]
=(x + 1)(x2 + x + 1)(x2 – x + 1)