Phân tích thành nhân tử: (x+2 )(x+4)( x+6 )(x+8) + 16
Giải thích
x+2x+4x+6x+8+16=x+2x+8x+4x+6+16=x2+10x+16x2+10x+24+16(A)Đặt x2+10x+20=tA=t−4t+4+16=t2−16+16=t2=x2+10x+202
x+2x+4x+6x+8+16=x+2x+8x+4x+6+16=x2+10x+16x2+10x+24+16(A)Đặt x2+10x+20=tA=t−4t+4+16=t2−16+16=t2=x2+10x+202