Phân tích thành nhân tử ab (a+b) -bc (b+c) +ac (a-c)
Giải thích
ab (a+b) -bc (b+c) +ac (a-c)
=aba+b−b2c−bc2+a2c−ac2=aba+b+a2c−b2c−ac2+bc2=aba+b+ca2−b2−c2a+b=aba+b+ca−ba+b−c2a+b=a+bab+ac−bc−c2=a+bab−bc+ac−c2=a+bba−c+ca−c=a+bb+ca−c
ab (a+b) -bc (b+c) +ac (a-c)
=aba+b−b2c−bc2+a2c−ac2=aba+b+a2c−b2c−ac2+bc2=aba+b+ca2−b2−c2a+b=aba+b+ca−ba+b−c2a+b=a+bab+ac−bc−c2=a+bab−bc+ac−c2=a+bba−c+ca−c=a+bb+ca−c