Phân tích đa thức thành nhân tử x^4 + 2018x^2 + 2017x + 2018
Giải thích
Ta có: x4+2018x2+2017x+2018
=x4−x+2018x2+2018x+2018
=xx3−1+2018x2+2018x+2018
=xx−1x2+x+1+2018x2+x+1
=x2+x+1x2−x+2018
Ta có: x4+2018x2+2017x+2018
=x4−x+2018x2+2018x+2018
=xx3−1+2018x2+2018x+2018
=xx−1x2+x+1+2018x2+x+1
=x2+x+1x2−x+2018