Phân tích đa thức sau thành nhân tử: x^2 + y^2 -x^2y^2 + xy -x -y
Giải thích
x2+y2−x2y2+xy−x−y=x2−x2y2+y2−y+xy−x=−x2y2−1+yy−1+xy−1=y−1−x2y+1+y+x=y−1.−x2y−x2+y+x=y−1y−x2y−x2−x=y−1−yx2−1−xx−1=y−1x−1−yx+1−x=y−1x−1−xy−y−x
x2+y2−x2y2+xy−x−y=x2−x2y2+y2−y+xy−x=−x2y2−1+yy−1+xy−1=y−1−x2y+1+y+x=y−1.−x2y−x2+y+x=y−1y−x2y−x2−x=y−1−yx2−1−xx−1=y−1x−1−yx+1−x=y−1x−1−xy−y−x