Phân tích đa thức sau thành nhân tử: (x^2 +2x) (x^2 +4x +3) -24

x2+2xx2+4x+3−24=x2+2xx2+4x+3−24=xx+2xx+1+3x+1−24=xx+2x+1x+3−24=x.x+3x+1x+2−24=x2+3xx2+3x+2−24   =x2+3x2+2x2+3x−24=x2+3x2+6x2+3x−4x2+3x−24=x2+3x2+6x2+3x−4x2+3x+24=x2+3xx2+3x+6−4x2+3x+6=x2+3x−4x2+3x+6

Vậy x2+2xx2+4x+3−24=x2+3x−4x2+3x+6