Lim x^2} - 121 / x + 11 bằng:
Giải thích
Chọn A
Ta có \(\mathop {\lim }\limits_{x \to - 11} {\mkern 1mu} \frac{{{x^2} - 121}}{{x + 11}} = \mathop {\lim }\limits_{x \to - 11} {\mkern 1mu} \frac{{\left( {x + 11} \right)\left( {x - 11} \right)}}{{x + 11}} = \mathop {\lim }\limits_{x \to - 11} {\mkern 1mu} \left( {x - 11} \right) = - 22\).