lim (x-> dương vô cùng) (1+3x)/ căn (2x^2+3)

chọn A

limx→−∞1+3x2x2+3 = limx→−∞1+3xx2+3x2=limx→−∞1+3x−x2+3x2=limx→−∞1x+3−2+3x2=−322