Lim X + 2023 / x-1 bằng
Giải thích
Chọn D
\(\left\{ \begin{array}{l}\mathop {\lim }\limits_{x \to {1^ - }} \left( {x + 2023} \right) = 2022\\\mathop {\lim }\limits_{x \to {1^ - }} \left( {x - 1} \right) = 0,{\rm{ }}x - 1 < 0,\forall x\end{array} \right.\)
Vậy \(\mathop {\lim }\limits_{x \to {1^ - }} \frac{{x + 2023}}{{x - 1}} = - \infty .\)