lim x → 2 3 f ( x ) = 2027 . b) lim x → 2 f ( x ) 4 = 506 .

15/22

Cho hàm số \(\mathop {\lim }\limits_{x \to 2} f\left( x \right) = 2024\). Khi đó:

a)\(\mathop {\lim }\limits_{x \to 2} 3f\left( x \right) = 2027\).

b)\(\mathop {\lim }\limits_{x \to 2} \frac{{f\left( x \right)}}{4} = 506\).

c)\(\mathop {\lim }\limits_{x \to 2} \sqrt {f\left( x \right)} = 2\sqrt {506} \).

d)\(\mathop {\lim }\limits_{x \to 2} \left[ {100x - \frac{1}{2}f\left( x \right)} \right] = - 812\).

Nhập câu trả lời ở đây

0/3000 ký tự

Giải thích

a) \(\mathop {\lim }\limits_{x \to 2} 3f\left( x \right) = 3\mathop {\lim }\limits_{x \to 2} f\left( x \right) = 3.2024 = 6072\).

b) \(\mathop {\lim }\limits_{x \to 2} \frac{{f\left( x \right)}}{4} = \frac{{2024}}{4} = 506\).

c) \(\mathop {\lim }\limits_{x \to 2} \sqrt {f\left( x \right)} = \sqrt {2024} = 2\sqrt {506} \).

d) \(\mathop {\lim }\limits_{x \to 2} \left[ {100x - \frac{1}{2}f\left( x \right)} \right] = \mathop {\lim }\limits_{x \to 2} 100x - \frac{1}{2}\mathop {\lim }\limits_{x \to 2} f\left( x \right)\)\( = 200 - \frac{1}{2}.2024 = - 812\).

Đáp án: a) Sai; b) Đúng; c) Đúng; d) Đúng.