Lim căn {5x - 1} - 3 / x - 2 = a/b
Giải thích
Chọn D
\(\mathop {\lim }\limits_{x \to 2} \frac{{\sqrt {5x - 1} - 3}}{{x - 2}} = \mathop {\lim }\limits_{x \to 2} \frac{{\left( {\sqrt {5x - 1} - 3} \right)\left( {\sqrt {5x - 1} + 3} \right)}}{{\left( {x - 2} \right)\left( {\sqrt {5x - 1} + 3} \right)}} = \mathop {\lim }\limits_{x \to 2} \frac{{5\left( {x - 2} \right)}}{{\left( {x - 2} \right)\left( {\sqrt {5x - 1} + 3} \right)}} = \mathop {\lim }\limits_{x \to 2} \frac{5}{{\sqrt {5x - 1} + 3}} = \frac{5}{6}\)
Vậy \[a + b = 11\].