Lim 3x - 2023 / x + 2024 bằng:
Giải thích
Chọn A
Ta có \(\mathop {\lim }\limits_{x \to - \infty } \frac{{3x - 2023}}{{x + 2024}}\)\( = \mathop {\lim }\limits_{x \to - \infty } \frac{{3 - \frac{{2023}}{x}}}{{1 + \frac{{2024}}{x}}} = 3\).
Chọn A
Ta có \(\mathop {\lim }\limits_{x \to - \infty } \frac{{3x - 2023}}{{x + 2024}}\)\( = \mathop {\lim }\limits_{x \to - \infty } \frac{{3 - \frac{{2023}}{x}}}{{1 + \frac{{2024}}{x}}} = 3\).