Lim 2x + 1 / x - 3 bằng
Giải thích
Chọn C
Ta có \(\mathop {\lim }\limits_{x \to {3^ - }} \frac{{2x + 1}}{{x - 3}} = - \infty \) vì \(\left\{ \begin{array}{l}\mathop {\lim }\limits_{x \to {3^ - }} \left( {2x + 1} \right) = 7 > 0\\\mathop {\lim }\limits_{x \to {3^ - }} \left( {x - 3} \right) = 0,x - 3 < 0,\forall x < 3\end{array} \right.\).