1.

a) \(\frac{5}{6} - \left( {\frac{1}{3} + \frac{1}{2}} \right):20\% \)\( = \frac{5}{6} - \left( {\frac{2}{6} + \frac{3}{6}} \right) \cdot 20\% \)

\( = \frac{5}{6} - \frac{5}{6} \cdot \frac{1}{5}\)\( = \frac{5}{6} - \frac{1}{6}\)\( = \frac{4}{6} = \frac{2}{3}\);

b) \(\frac{3}{{17}}.\frac{6}{{29}} - \frac{3}{{17}}.\frac{{35}}{{29}} + 2022\frac{3}{{17}}\)\( = \frac{3}{{17}} \cdot \left( {\frac{6}{{29}} - \frac{{35}}{{29}}} \right) + 2022\frac{3}{{17}}\)

\( = \frac{3}{{17}} \cdot \left( {\frac{{ - 29}}{{29}}} \right) + 2022\frac{3}{{17}}\)\( = \frac{3}{{17}} \cdot \left( { - 1} \right) + 2022\frac{3}{{17}}\)

\( = \frac{{ - 3}}{{17}} + 2022\frac{3}{{17}} = 2022\).

2.

a) \[\frac{{11}}{8} - \frac{3}{8} \cdot x = \frac{1}{8}\]

\[\frac{3}{8} \cdot x = \frac{{11}}{8} - \frac{1}{8}\]

\[\frac{3}{8} \cdot x = \frac{{10}}{8}\]

\[x = \frac{{10}}{8}:\frac{3}{8}\]

\[x = \frac{{10}}{3}\].

Vậy \[x = \frac{{10}}{3}\].

b) \({\left( {x - \frac{1}{2}} \right)^2} = \frac{1}{4}\)

• TH1: \(x - \frac{1}{2} = \frac{1}{2}\)

\(x = \frac{1}{2} + \frac{1}{2}\)

\(x = 1\).

• TH2: \(x - \frac{1}{2} = \frac{{ - 1}}{2}\)\(x = \frac{{ - 1}}{2} + \frac{1}{2}\)

\(x = 0\).

Vậy \(x = 1\,;\,\,\,x = 0\).

Kết quả của phép tính - 15/14.49/35 bằng: