Hãy xác định giá trị tích chập vòng của hai dãy sau x 1 ( n ) 3 = δ ( n ) + δ ( n − 1 ) x 2 ( n ) 3 = 1 2 δ ( n )

$\text{x}(\text{n}){}_3=\left\{2,3/2,5/2\right\}\cdot \text{u}\left(\text{n}\right)$

$\text{x}(\text{n}){}_3=\left\{1/2,3/2,5/2,3/2\right\}\cdot \text{u}\left(\text{n}\right)$

$x(n){}_3=\left\{1/2,3/2,5/2,3/2,0,\dots \right\}\cdot u\left(n\right)$

$\text{x}(\text{n}){}_3=\left\{1/2,3/2,5/2\right\}\cdot \text{u}\left(\text{n}-2\right)$