Gieo con súc sắc hai lần. Gọi \[A\] là biến cố để sau hai lần gieo có ít nhất một mặt 6 chấm. Biến cố \[A\] là

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\[A = \left\{ {\left( {6,1} \right),\,\left( {6,2} \right),\,\left( {6,3} \right),\,\left( {6,4} \right),\,\left( {6,5} \right)} \right\}\].

\[A = \left\{ {\left( {1;6} \right),\,\left( {2;6} \right),\,\left( {3;6} \right),\,\left( {4;6} \right),\,\left( {5;6} \right)} \right\}\].

\[A = \left\{ {\left( {1,6} \right),\,\left( {2,6} \right),\,\left( {3,6} \right),\,\left( {4,6} \right),\,\left( {5,6} \right),\,\left( {6,6} \right)} \right\}\].

\[A = \left\{ {\left( {1,6} \right),\,\left( {2,6} \right),\,\left( {3,6} \right),\,\left( {4,6} \right),\,\left( {5,6} \right),\,\left( {6,6} \right),\,\left( {6,1} \right),\,\left( {6,2} \right),\,\left( {6,3} \right),\,\left( {6,4} \right),\,\left( {6,5} \right)} \right\}\].

Giải thích

Ta có biến cố\(A = \left\{ {\left( {1,6} \right),{\mkern 1mu} \left( {2,6} \right),{\mkern 1mu} \left( {3,6} \right),{\mkern 1mu} \left( {4,6} \right),{\mkern 1mu} \left( {5,6} \right),{\mkern 1mu} \left( {6,6} \right),{\mkern 1mu} \left( {6,1} \right),{\mkern 1mu} \left( {6,2} \right),{\mkern 1mu} \left( {6,3} \right),{\mkern 1mu} \left( {6,4} \right),{\mkern 1mu} \left( {6,5} \right)} \right\}\).